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8/18/2019 Ejercicio 1 Fase_cd
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8/18/2019 Ejercicio 1 Fase_cd
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lim∅
0−→sin 3 θ
5∅=¿> MULTIPLICAMOSLA FUNCIÓN SENO POR 3 θ , I!IIMOS POR 3 θ
lim∅
0
3 θ(sin 3θ
3
θ
)
5 =¿>3
5 lim
∅0−→
sin 3
θ5∅ =¿>3
5∗1=3
5
L!"!TE ES#EC!$L=1
R//lim∅
0−→sin3θ
5∅=3
5
•
lim "
0−→sin 4 "
3 " limite especial lim
" 0−→
sin " "
=1
Entonces:
lim∅
0−→sin 4 "
3 " =¿> Multiplicamos la #unci$n SEN " po%4 " & la'i(i'imos po% 4 "
lim "
0
4 " ( sin 4 " 4 " )3 "
=¿> lim "
0
4( sin 4 " 4 " )3
=¿>4
3 lim "
0−→sin 4 "
3 " =¿>
4
3∗1=
4
3
L!"!TE ES#EC!$L
R//lim∅
0−→sin 4 "
3 " =
4
3
8/18/2019 Ejercicio 1 Fase_cd
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