programacion determinista

7/17/2019 programacion determinista

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Etapa 3F3(s3, x3)= 14x3

S3 X3= 0 X3= 1 X3= 2 X3= 3 X4= 4 f 3*(S3) X3*0 14(0)=0 - - - - 0 01 14(0)=0 14(1)= 14 - - - 14 12 14(0)=0 14(1)= 14 14(2)= 28 - - 28 2

3 14(0)=0 14(1)= 14 14(2)= 28 14(3)= 42 - 42 34 14(0)=0 14(1)= 14 14(2)= 28 14(3)= 42 14(4)= 56 56 4

S3=0; Significa q! !" ca#i$n !st% ""!n&, 'isp&nii"i'a' '! c!&

S3= 4; Significa q! !" ca#i$n !sta +aci&, 'isp&nii"i'a' '! 4t&n

Etapa 2f 2(S2, X2)= 4X2 f 3*(s2-3x2)

S2 X2= 0 X2= 1 f 2*(S2) X2*

0 4(0)0= 0 - 0 01 4(0)14= 14 - 14 02 4(0)28= 28 - 28 03 4(0)42= 42 4(1)0=4 4 14 4(0)56= 56 4(1)14= 61 61 1

Etapa 1F1(S1, X1) 31X1f 2*(S1-2X1)

S1 X1= 0 X1= 1 X1= 2 F1(S1) X1*0 31(0)0= 0 - - 0 0

1 31(0)14= 14 - - 14 02 31(0)28= 28 31(1)0= 31 - 31 13 31(0)4=4 31(1)14= 45 - 4 04 31(0)61= 61 31(1)28= 5. 31(2)0= 62 62 2

Solución:

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