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7/24/2019 SOLUCION DE LA INTEGRAL DE DUHAMEL CON MATHCAD
1/3
1.-PROBLEMA 01: SOLUCION UTILIZANDO LA INTEGRAL DE DUHAMEL(CON MATHCAD PRIME 3.1)
k1 15.65 m1 2 wn1 88.46 Tn1 2
wn1
=Tn1 0.071
P1 t 15 sin 40 t
A1 t d0
t
P1 x cos wn1 x x
B1 t d0
t
P1 x sin wn1 x x
u1 t
32.3
m1 wn1 A1 t sin wn1 t B1 t cos wn1 t
f1 t k 1 u 1 t
v1 t d
dtu1 t
t , 0 0.01 2
-0.6
-0.45
-0.3
-0.15
0
0.15
0.3
0.45
0.6
0.75
-0.9-0.75
0.9
0.4 0.6 0.8 1 1.2 1.4 1.6 1.80 0.2 2
t
f1 t
7/24/2019 SOLUCION DE LA INTEGRAL DE DUHAMEL CON MATHCAD
2/3
2.-PROBLEMA 02: SOLUCION UTILIZANDO LA INTEGRAL DE DUHAMEL(CON MATHCAD PRIME 3.1)
k2 237.926 m2 5 wn2 6.8982 Tn2 2 wn2
=Tn2 0.911
P2 t 16 t 4
A2 t d0
t
P2 x cos wn2 x x
B2 t d0
t
P2 x sin wn2 x x
u2 t 32.3
m2 wn2A2 t sin wn2 t B2 t cos wn2 t
f2 t k2 u2 t
v2 t d
dtu2 t
t , 0 0.01 3
150
300
450
600
750
900
1.0510
1.210
1.3510
-150
0
1.510
0.6 0.9 1.2 1.5 1.8 2.1 2.4 2.70 0.3 3
t
f2 t
7/24/2019 SOLUCION DE LA INTEGRAL DE DUHAMEL CON MATHCAD
3/3
3.-PROBLEMA 03: SOLUCION UTILIZANDO LA INTEGRAL DE DUHAMEL(CON MATHCAD PRIME 3.1)
k3 7714.51 wn3 55.55 Tn3 2 wn3
=Tn3 0.113 a 0.7m3 2.5
P3 t 2.5 0.7 9.8
A3 t d0
t
P3 x cos wn3 x x
B3 t d0
t
P3 x sin wn3 x x
u3 t
32.3
m3 wn3 A3 t sin wn3 t B3 t cos wn3 t
f3 t k3 u3 t
v3 t d
dtu3 t
t , 0 0.005 1
-950
-850
-750
-650
-550
-450
-350
-250
-150
-50
-1.1510
-1.0510
50
0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.90 0.1 1
t
f3 t
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