DISEÑO DE MUROS EN VOLADIZO

DATOS

Ƴs = 2.10 T/m3Ƴc = 2.40 T/m3

Ø = 32 °fc = 210 Kg/cm2fy = 4200 Kg/cm2

ϭt = 2.88 Kg/cm2S/C = 2.20 T/m2

hp = 4.00 mFSD = 1.5FSV = 2

f = 0.625 > 0.6Usar f = 0.600

Ka = 0.307

ho = 1.048

DIMENSIONAMIENTO DE LA PANTALLA

t 1 = 0.30 m

Mu = 22.12 T.m

Usando : ρ = 0.004

w = 0.08

Ø = 0.9b = 100

d = 40.00 cm

➱ t 2 = 45.00 cm Usar t2= 0.45 md = 0.40 m

VERIFICACION POR CORTE

Vud = 11.9064 T

Ø = 0.85 Vud/Ø = 14.01 T

Vc = 30.72 T >Vud/Ø OK !

Si hay traslape en la base Vce = 20.48 T >Vud/Ø OK !

Como el Angulo del talud = 0°

f=tg φ

Ka=tg2(45− φ2 )

hO=SCγ S

Mu=1 .8⋅[Ka⋅γ S⋅hP36 +Ka⋅γ S⋅hO⋅hP2

2 ]ω=ρ⋅

fyfc

d=√ Muφ⋅b⋅fc⋅ω⋅(1−0 .59⋅ω)

t2=d+5cm

V ud=1 .8⋅[Ka⋅γ S⋅(hP−d )2

2+Ka⋅γ S⋅hO⋅(hP−d )]

Vc=0 .53⋅√ fc⋅b⋅dVce=

23Vc

B1

t2

t1

B

hzhp

B2

ht

DIMENSIONAMIENTO DE LA ZAPATA

hz = 0.50 mUsamos hz= 0.50 m

h = 4.50 m

Ƴm = 2.00 T/m3 B1 ≥ 1.81 m

B1 = 1.89 m Usamos B1= 2.50 m

B2 ≥ 0.26 m

B2 mín = 0.50 m Usamos B2= 0.50 m

➱ B = 3.00 m

VERIFICACION DE ESTABILIDAD

AREA P.E. PESO x P.x 9.57 T

A1 1.20 2.40 2.88 0.80 2.30A2 0.30 2.40 0.72 0.60 0.43A3 1.50 2.40 3.60 1.50 5.40 16.64 T.mA4 8.20 2.10 17.22 1.98 34.01

N = 24.42 42.15

FSD = 1.53 > 1.5 OK !

FSV = 2.53 > 2 OK !

PRESIONES SOBRE EL TERRENO

Xo = 1.04 m

e = 0.46 m

B/6 = 0.50 m > e OK !

q1 = 15.56 T/m2 < σt OK !

q2 = 0.72 T/m2

EA =

MA =

MR =

Vce=23Vc

hZ=t2+5⋅cm

h=hP+hZ

B1h

≥FSDKa⋅γ S2⋅f⋅γm

B2h

≥ f3⋅FSVFSD

−B12⋅h

B2mín=hZ

B=B1+B2

E A=Ka⋅γ S⋅hO⋅h+Ka⋅γ S⋅h2

2

M A=Ka⋅γ S⋅hO⋅h2

2+Ka⋅γ S⋅

h3

6

FSD=f⋅NE A

FSV=M R

M A

Xo=MR−M A

N

e=B2

−Xo

qalignl ¿ 1 ¿2 ¿=NB [1±6⋅eB ]¿

E1

E2

S/C

A4A1

A2

A3

DISEÑO

DISEÑO DE LA PANTALLA

b = 100 cmd = 40 cm

t1 = 30 cmt2 = 45 cmfc = 210 Kg/cm2fy = 4200 Kg/cm2Ø = 0.9

Asmín = 5.40 cm2

Asmín = 8.10 cm2

# fierro @Mu = 22.12 T.m As = 15.32 cm2 4 0.08 m

Corte de 1 fierro alterno# fierro

4 0.125 ➱ ρ' = 0.0013

ρmín = 0.0018

REFUERZO HORIZONTAL

Arriba # fierro @As = 6.00 cm2

2/3As = 4 cm2 4 0.32 m1/3As = 2 cm2 3 0.36 m

IntermedioAs = 7.50 cm2

2/3As = 5 cm2 4 0.25 m1/3As = 2.5 cm2 3 0.29 m

AbajoAs = 9.00 cm2

2/3As = 6 cm2 4 0.21 m1/3As = 3 cm2 3 0.24 m

S usado

Asmín=0 .0018⋅b⋅t1

Asmín=0 .0018⋅b⋅t2

As=0.002⋅b⋅t

DISEÑO DE LA ZAPATA

Ws = 8.40 T/m q1 = 15.56 T/m

Wz = 1.20 T/m q2 = 0.72 T/m

ZAPATA ANTERIOR

Wu = 26.93 T/m

Mu = 3.37 T.m# fierro @

As = 2.24 cm2 4 0.57 md = 41.00 cm

As mín= 7.38 cm2 4 0.17 m

ZAPATA POSTERIOR

q = 10.139 T/m q' = 10.86 T/m

Wu = 14.4 T/m

Mu = 16.58 T.m# fierro @

As = 11.04 cm2 4 0.11 m

Refuerzo Transversal# fierro @

Astemp = 9.00 cm2 4 0.14 m

Wu=1 .8⋅q1−Wz⋅0 .9

Mu=Wu⋅L2

2

Asmín=0 .0018⋅b⋅d

Wu=(Ws+Wz )⋅1.5

Mu=(Wu−q2⋅1.5 )⋅L2

2−q '⋅1 .5⋅L

2

6