2013B TG5 Movimiento Curvilineo

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  • 5/26/2018 2013B TG5 Movimiento Curvilineo

    1/5

    x= 12

    (0, 2 t)

    y= 10

    (0, 2 t)

    z= 0, 8 t

    r =

    5(cos 2t) i+ 4(sen 2t) j

    t

    t= 1

    vx = 2, 4 1, 6 t

    2

    vy = 4, 0 t v t

    t = 0s

    35, 0

    4000 m

    g = 9, 8 m/s2

    v0

    (v0)

    D

    g

    B

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    vA

    h

    B

    (y 40)2 = 160x

    vy =

    x = 5 t

    y = 2/t

    t

    t= 1s

    t= 1s

    y = 0,4x2

    xA =

    yA = 1,6 vB =

    dvB/dt =

    2

    vA = 8 A =

    y = f(x)

    t=

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    r(t)

    (t)

    r =

    r

    r =

    =

    r =

    2

    =

    4

    2

    m/s2

    t= 1s.

    30m/s

    20

    60km/h

    = 90

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    vB = 10

    vA = 5

    20 m/s

    5m/s2

    80 m

    v

    R

    x= R(t

    sent)

    y=R(1 cost)

    = v/R.

    r

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    R

    vo

    x = R(t

    sent

    y = R(1 cost) = V o/R

    t

    r = 75 mm

    =

    5 rad/s2

    t1

    t = 0

    t= t1

    t= t1