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xs 2,38567=x 12,7925= ∈ xs 2,38567 0,53345n 20
= = =
0
0
x 0,79250
12,79250 0,79250 12
− μ =
↓μ = − =
0 1H : 12 H : 12μ = μ ≠p
0/ 2
x
x 0,79250t 1,4860,53345s / nα
− μ= = =
[ ]p 19 19x xP t 1,486 2 P t 1,486 2 0,077 0,154⎡ ⎤α = > = > = =⎣ ⎦
1,7291 1,3277 1,4856 1,3277TABLAS: x 0,0770,05 0,10 x 0,10
− −= → =
− −
x 12,7925=
∈ xs 0,53345n
= =
0,025 ,190,7925t 2,093+ 0,3240
= =0,53345
0 1H : 12 H : 12μ = μ ≠
[ ]∈0 /2I ( x ) t .α= − μ ±
∈0 0,025 ,19 0,025 ,19L.I ( x ) t . 0,7925 t .= − μ − = − 0,3240 → − 0,53345 =− 0,3240
0x x 12 0,79250− μ = − =
∈0 0,025 ,19L.S ( x ) t . 0,7925 2,093 . 1,9090= − μ + = 0,79250 → + 0,53345 =
1,9090
p 00,154 0,05 Se acepta Hα = > = α →
0 1Contraste bilateral: H : 12 H : 12• μ = μ ≠
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