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Cálculo Numérico - EDO.pdf
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!"#$%&' (
!"#$%! &' ()#*$+', -./'0'1.*.,
!"#$% &'$()*+,% *-$-#',/$% *+ *-0*-1,'", * $!#',% "2-",% &$/*+ %*'
3$'+!),/$% *+ #*'+$% /* *4!,56*% /"3*'*-","% -, 3$'+,
y = f(x, y)
$-/* f 7 !+, 3!-58$ '*,) /,/,9 /* /!,% :,'";:*"% x * y9 * y 7 !+, 3!-58$ "-
!" #$%&'& '( )*+(, -"
+&.&/ 0(+1 &3'456& 43441+ '1'1/ $ .1,13%4'1 1 (748%9341 '( *:1 ;341 8&+*56& 01,1
& 0,&
!" #$%&'& '( )*+(, -.
/01*,2 !"3 4(5,(6(7%289& 1,:;2 '& =$%&'& '( )*+(,!
n xn yn f(xn, yn) h.f(xn, yn)0 0 1 5 2, 5
>&%( ?*( f(xn, yn) = 10+4.1 = 5! @1&,2A B2=&6 5,((7C(, 2 6(1*7'2 +07C2A 52,2
n = 1! D(1*7'2 2 (?*289& !"A xn+1 = xn+hA (7%9& x2 = x1+h = 0+0, 5 = 0, 5! E
B2+&, '( y2A 6(1*7'& 2 (?*289& !.A $ '2'& 5&, yn+1 = yn + h.f(xn, yn) = 1 + 2, 5 =
3, 5! )7%9&
n xn yn f(xn, yn) h.f(xn, yn)0 0 1 5 2, 51 0, 5 3, 5 14, 5 7, 3
F,((7C(7'& %&'2 2 %2G(+2A %(=&63
H&1&A & B2+&, '( y 52,2 2 ?*07%2 0%(,289& $ 01*2+ 2 96, 5!
I&=& 5&'( 6(, B06%&A & =$%&'& '( )*+(, ,(?*(, *= 7J=(,& =*0%& 1,27'( '(
0%(,28K(6 52,2 6( 2+2782, *= ,(6*+%2'& 62%06L2%M,0&! D9& 5,&5&6%26 =(+C&,026 52,2
& =$%&'&A &=& 6(,: B06%& 2 6(1*0,!
!#$%& '#(()%&!*( + ,-.!.& /!01*#&
!" #$%&'& '( )*+,(-.*%%/ 01
n xn yn f(xn, yn) h.f(xn, yn)0 0 1 5 2, 51 0, 5 3, 5 14, 5 7, 32 1 10, 7 43 21, 53 1, 5 32, 3 128, 5 64, 3
4 2 96, 5 385 192, 5
!" #$%&'& '( )*+,(-.*%%/
2 3$%&'& '( )*+,(-.*%%/ $4 56&7/7(83(+%(4 *3 '&9 3$%&'&9 3/:9 5&5*8/6(9 (
56(:9&9 5/6/ / && '( 9&8*=?(9 /56&@:3/'/9 '( (A*/=?(9 ':B(6(+:/:9! C3& !1F
yn+1 = yn +h
6(k1 + 2k2 + 2k3 + k4) G !1H
&+'(
k1 = f(xn, yn)
k2 = f(xn +h
2, yn +
h
2k1) G !0H
k3 = f(xn +h
2, yn +
h
2k2)
k4 = f(xn + h, yn + hk3)
!"#$%& '()(* /"0102,($# # !"#$# $% &'()%*+'"",3 ,1'1% ' , ,5.#60 ,78# $%
y(1, 5) 5,., , 9#1'78# $% y = 2xy3 y(1) = 13 # h = 0, 1:
;#1'78#
I/3&9 :+::/6 &3 &9 E8*8&9 '( k14 k24 k3 ( k4 / 5/6%:6 '/ (A*/=>& !JF
K/6/ n = 04
!#$%& '#(()%&!*( + ,-.!.& /!01*#&
!" #$%&'& '( )*+,(-.*%%/ 00
k1 = f(xn, yn)
= f(x0, y0)
= 2.x0.y0
= 2.1.1
= 2
k2 = f(xn +h
2, yn +
h
2k1)
= f(x0 +h
2, y0 +
h
2k1)
= f(1 +0, 1
2, 1 +
0, 1
2.2)
= f((1, 05), (1, 1))
= 2.(1, 05).(1, 1)
= 2, 31
k3 = f(xn +h
2, yn +
h
2k2)
= f(x0 +h
2, y0 +
h
2k2)
= f(1 +0, 1
2, 1 +
0, 1
2(2, 31))
= f((1, 05), (1, 1155))
= 2.(1, 05).(1, 1155)
= 2, 3425
k4 = f(xn + h, yn + hk3)
= f(x0 + h, y0 + k3)
= f((1 + 0, 1), (1 + 0, 1.(2, 3425)))
= f((1, 1), (1, 2342))
= 2.(1, 1).(1, 2342)
= 2, 7154
1,&2/3 4*54%6%*6+'& +/ (7*/89& !:
!#$%& '#(()%&!*( + ,-.!.& /!01*#&
!" #$%&'& '( )*+,(-.*%%/ 01
yn+1 = yn +h
6(k1 + 2k2 + 2k3 + k4)
y1 = y0 +h
6(k1 + 2k2 + 2k3 + k4)
= 1 +0, 1
6(2 + 2.(2, 31) + 2.(2, 3425) + 2, 7154)
= 1, 2337
)(/234/+'& & 5(65& 78&(66& /%$ x = 1, 5: &* 6(;/ y(1, 5) &
!"!#$%'() *'+,'-.#/"'() !
{y = y1/3
y(0) = 0
x [0; 0, 3]; h = 0, 1
!
{xy = x y
y(2) = 2
"#$&$' y(2, 1) () h = 0, 1*
"!
{y = 2y
x+1+ (x+ 1)3
y(0) = 3
x [0; 0, 2]; h = 0, 1
01'(%- *'22!%-1#2 3 4/,1,- 5167#'-