DISEO DE ESCALERA - UN TRAMO + DESCANSO

DATOS

f'c =fy =

S/C =Acabados =

b =CP =

P =t =

Recub =

hm =

0.25 m 2.00 m 2.40 m 0.40 m

1. PREDIMENSIONADOEspesor de la escalera

t = Ln/20 = 0.22 m Jose Luis Reque Quesquent = Ln/25 = 0.18 m Estudiante de Ingenieria Civil - UNPRG

USAR t = 0.20 m Lambayeque - Peru

2. METRADO DE CARGASWu2

Wu1

2.125 m 2.600 mX RB

Wu1 TRAMO DESCANSOCarga Muerta Carga Viva

P.P = 576.00 Kg/m S/C = 720.00 Kg/mAcabados = 120.00 Kg/m

696.00 Kg/m 720.00 Kg/m

C =

2cos2CPtCPhhm

WD1 = 835.20 Kg/m WL1 = 1152.00 Kg/m Wu1 = 1987.20 Kg/m

Wu2 TRAMO PASOSCarga Muerta Carga Viva

P.P = 899.55 Kg/m S/C = 720.00 Kg/mAcabados = 120.00 Kg/m

1019.55 Kg/m 720.00 Kg/mWD1 = 1223.47 Kg/m WL1 = 1152.00 Kg/m Wu2 = 2375.47 Kg/m

3. CALCULO DE MOMENTORB = 5426.51 Kg

El momento maximo se dar en la seccion que posea el cortante igual a 0Vx = 0 X = 2.28 m

(+) Mu max = 6198.15 Kg-m(+) M diseo = 4958.52 Kg-m = 4.96 T-m

4. DISEO EN ACEROPara Momento Positivo: 4.96 T-mAsumiendo varilla de acero: 1/2

b = 120.00 cm As = 1.27 cmd = 17.37 cma = 1.55 cm USAR = 7 1/2 @ 19

As (+) = 7.91 cm Ok!As (+) = 7.91 cm

S = 19.00 cm# Varillas = 7

As min = 3.75 cm

Para Momento Negativo: 3/8Asumiendo varilla de acero: As = 0.71 cm

As (-) = 2.64 cm Colocar As minAs (-) = 3.75 cm USAR = 6 3/8 @ 22.5

S = 22.50 cmS max = 60.00 cmS max = 45.00 cm

=

=

S = 22.50 cm# Varillas = 6

Para As de Temperatura:As temp = 3.60 cmAs temp = 1.80 cm Dos capasAsumiendo varilla de acero: 3/8

S = 39.50 cm As = 0.71 cmS max = 100.00 cmS max = 45.00 cm USAR = 3/8 @ 39.5

S = 39.50 cm

=

DISEO DE ESCALERA - UN TRAMO + DESCANSO

DISTRIBUCION DE ACERO

210.00 Kg/cm 7 1/2 @ 194200.00 Kg/cm 6 3/8 @ 22.5600.00 Kg/m 3/8 @ 39.5100.00 Kg/m

1.20 m0.18 m0.30 m30.96 0.20 m2.00 cm

2400.00 Kg/m30.31 m

Estudiante de Ingenieria Civil - UNPRG

2cos2CPtCPhhm

ESCALERA