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TEMPERATURA 10°C 20 masa 2 TIEMPO VELOCIDAD TIEMPO g kg s m/s s 3 0.003 6.52 0.0613 2.6 4 0.004 8.14 0.0491 3.1 5 0.005 10.33 0.038 4.28 6 0.006 16.33 0.0245 6.39 0.00 32.98 0.0121 12.94 10°C 20°C 30°C a 0.0987108113 0.2481261855 0.6058167427 m -12.3087515256 -30.945366175 -75.896084254 R2 0.998004333 0.9993900774 0.9999381387 Determinacion de la viscocidad T°C 10 20 30 K 3.843803646 1.5289013 0.62338426 T 283 293 303 1/T 0.0035 0.0034 0.0033 ! 3.8438 1.5289 0.6234 0.002 0.003 0.004 0.005 0.006 0.0 0.0000 0.0500 0.1000 0.1500 0.2000 0.2500 0.3000 0.3500 0.4000 "#$% & ' 5.8960842539$ ( 0.60581 R) & 0.999938138 "#$% & ' 30.945366151$ ( 0.24812 R) & 0.99939004 "#$% & ' 12.308515256$ ( 0.0981 R) & 0.998004333 Chart Title masa2 Kg velocidad m/s

EJEMPLO 1

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Ejemplo grafico de un ejercicio de transferencia de calor con datos propuestos

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Hoja1TEMPERATURA10C20C30CCONSTANTES EN EL EXPERIMENTOmasa 2TIEMPOVELOCIDADTIEMPOVELOCIDADTIEMPOVELOCIDADgkgsm/ssm/ssm/sDistancia40cm30.0036.520.06132.60.15381.060.37740.4m40.0048.140.04913.170.12621.320.3030radio1.1cm50.00510.330.03874.280.09351.760.22730.011m60.00616.330.02456.390.06262.680.1493masa 115g70.00732.980.012112.940.03095.350.07480.015densidad del fluido1.26g/cm 31260Kg/M3gravedad9.81m/s 23.1415926536R8.314J((mol K)Ea del agua14.9KJ/(mol k)10C20C30Ca0.09871081130.24812618550.6058167427m-12.3087515256-30.9453661751-75.8960842539R20.9980043330.99939007740.9999381387Determinacion de la viscocidadTC102030K3.8438036461.52890173360.6233842557Pa.sT283293303K1/T0.00350.00340.0033K (-1)K3.84381.52890.6234Pa.sLN (K)1.34646240920.4245496565-0.4725921675Determinar la energia de activacionLn k-26.1997816399Ko0m7797.2862630472R 20.9998598127Ea64826.6379909745J/mol K64.826637991KJ/mol K

Hoja2

Hoja3