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UNIVERSIDAD COOPERATIVA DE COLOMBIA PRESENTADO A: Docente Jorge Alejandro Obando Bastidas PRESENTADO POR: Jhoana Veloza Marcela Carrillo Natalia Rojas CLASE: Estadística Descriptiva ‘502’ FECHA: 26 De Marzo de 2015

Ejercicio 26 de Marzo

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Page 1: Ejercicio 26 de Marzo

UNIVERSIDAD COOPERATIVA DE COLOMBIA

PRESENTADO A:Docente Jorge Alejandro Obando Bastidas

PRESENTADO POR:Jhoana VelozaMarcela CarrilloNatalia Rojas

CLASE:Estadística Descriptiva ‘502’

FECHA:26 De Marzo de 2015

VILLAVICENCIO

Page 2: Ejercicio 26 de Marzo

EJERCICIO EN CLASE

datos=c(4.5,2.3,1.0,5.0,3.2,2.8,3.5,4.2,5.0,3.2,1.8,2.9,3.9,4.2,3.3,1.8,2.9,4.4,3.3,1.7,1.0,3.8,4.2,3.1,1.7,1.5,2.6,3.3,3.8,4.1,4.4,4.5,4.0,3.5,3.3,2.1,2.7,3.3,2.2,4.6,4.1,4.4,3.3,4.8,4.4)

> datos

[1] 4.5 2.3 1.0 5.0 3.2 2.8 3.5 4.2 5.0 3.2 1.8 2.9 3.9 4.2 3.3 1.8 2.9 4.4 3.3

[20] 1.7 1.0 3.8 4.2 3.1 1.7 1.5 2.6 3.3 3.8 4.1 4.4 4.5 4.0 3.5 3.3 2.1 2.7 3.3

[39] 2.2 4.6 4.1 4.4 3.3 4.8 4.4

> Rango=Max(datos)-min(datos)

Error: no se pudo encontrar la función "Max"

> Rango=max(datos)-min(datos)

> Rango

[1] 4

> m=round(1+3.3*log10(45))

> m

[1] 6

> c=Rango/m

> m

[1] 6

> c

[1] 0.6666667

> c*m

[1] 4

> Inicio*min(datos)-0.1

Error: objeto 'Inicio' no encontrado

Page 3: Ejercicio 26 de Marzo

> Inicio=min(datos)-0.1

>

> C=0.7

>

> c

[1] 0.6666667

> C=0.7

> C*m

[1] 4.2

>

> inicio=min(datos)-0.

> inicio=min(datos)-0.1

> final=max(datos)+0.2

> cbind(inicio,final)

inicio final

[1,] 0.9 5.2

> final=max(datos)+0.1

> cbind(inicio,final)

inicio final

[1,] 0.9 5.1

> intervalos=cut(datos)

Error en cut.default(datos) :

el argumento "breaks" está ausente, sin valor por omisión

> intervalos=cut(datos,bread=c(0.9,5.1)

+ intervalos

Page 4: Ejercicio 26 de Marzo

Error: inesperado símbolo in:

"intervalos=cut(datos,bread=c(0.9,5.1)

intervalos"

> intervalos=cut(datos,bread=c(0.9,5.1)

+ intervalos=cut(datos,breads=c(0.9,5.1)

Error: inesperado símbolo in:

"intervalos=cut(datos,bread=c(0.9,5.1)

intervalos"

> intervalos=cut(datos,breaks=c(0.9,5.1)

+ intervalos

Error: inesperado símbolo in:

"intervalos=cut(datos,breaks=c(0.9,5.1)

intervalos"

> intervalos=cut(datos,breaks=c(0.9,1.6,2.3,3.3,3.7,4.4,5.1))

> intervalos

[1] (4.4,5.1] (1.6,2.3] (0.9,1.6] (4.4,5.1] (2.3,3.3] (2.3,3.3] (3.3,3.7]

[8] (3.7,4.4] (4.4,5.1] (2.3,3.3] (1.6,2.3] (2.3,3.3] (3.7,4.4] (3.7,4.4]

[15] (2.3,3.3] (1.6,2.3] (2.3,3.3] (3.7,4.4] (2.3,3.3] (1.6,2.3] (0.9,1.6]

[22] (3.7,4.4] (3.7,4.4] (2.3,3.3] (1.6,2.3] (0.9,1.6] (2.3,3.3] (2.3,3.3]

[29] (3.7,4.4] (3.7,4.4] (3.7,4.4] (4.4,5.1] (3.7,4.4] (3.3,3.7] (2.3,3.3]

[36] (1.6,2.3] (2.3,3.3] (2.3,3.3] (1.6,2.3] (4.4,5.1] (3.7,4.4] (3.7,4.4]

[43] (2.3,3.3] (4.4,5.1] (3.7,4.4]

Levels: (0.9,1.6] (1.6,2.3] (2.3,3.3] (3.3,3.7] (3.7,4.4] (4.4,5.1]

> f=table(intervalos)

> f

Page 5: Ejercicio 26 de Marzo

intervalos

(0.9,1.6] (1.6,2.3] (2.3,3.3] (3.3,3.7] (3.7,4.4] (4.4,5.1]

3 7 14 2 13 6

> n=sum(f)

> h=f/n

> F=cumsum(f)

> H=cumsum(h)

> cbind(f,h,F,H)

f h F H

(0.9,1.6] 3 0.06666667 3 0.06666667

(1.6,2.3] 7 0.15555556 10 0.22222222

(2.3,3.3] 14 0.31111111 24 0.53333333

(3.3,3.7] 2 0.04444444 26 0.57777778

(3.7,4.4] 13 0.28888889 39 0.86666667

(4.4,5.1] 6 0.13333333 45 1.00000000

> lindsum=c(1.6,2.3,3.3,3.7,4.4,5.1)

> lindsum=c(0.9,1.6,2.3,3.3,3.7,4.4)

> Marca=(lindsup+liminf)/2

Error: objeto 'lindsup' no encontrado

> Marca=(limsup+liminf)/2

Error: objeto 'limsup' no encontrado

> marca=(limsup+liminf)/2

Error: objeto 'limsup' no encontrado

> limsup=c(0.9,1.6,2.3,3.3,3.7,4.4)

> limsup=c(1.6,2.3,3.3,3.7,4.4,5.1)

Page 6: Ejercicio 26 de Marzo

> liminf=c(0.9,1.6,2.3,3.3,3.7,4.4)

> marca=(limsup+liminf)/2

> X=f*marca

> X

intervalos

(0.9,1.6] (1.6,2.3] (2.3,3.3] (3.3,3.7] (3.7,4.4] (4.4,5.1]

3.75 13.65 39.20 7.00 52.65 28.50

> cbind(f,marca,x)

Error en cbind(f, marca, x) : objeto 'x' no encontrado

> cbind(f,Marca,x)

Error en cbind(f, Marca, x) : objeto 'Marca' no encontrado

> cbind(f,Marca,X)

Error en cbind(f, Marca, X) : objeto 'Marca' no encontrado

> cbind(f,marca,X)

f marca X

(0.9,1.6] 3 1.25 3.75

(1.6,2.3] 7 1.95 13.65

(2.3,3.3] 14 2.80 39.20

(3.3,3.7] 2 3.50 7.00

(3.7,4.4] 13 4.05 52.65

(4.4,5.1] 6 4.75 28.50

> media=sum(X)/n

> media

[1] 3.216667

>