TEORIA DE LA PROBABILIDAD - SOLUCIONES 1. 1. ) ( ) ( B A B A ∪ ∩ ∪ = A 2. ) ( ) ( B A B A − ∪ ∩ = A 2. 3 2 1 A A A D a ∩ ∩ = 3 2 1 A A A D b ∪ ∪ = = ∩ ∩ ∪ ∩ ∩ ∪ ∩ ∩ ∪ ∩ ∩ = ) ( ) ( ) ( ) ( 3 2 1 3 2 1 3 2 1 3 2 1 A A A A A A A A A A A A D c ) ( ) ( ) ( 3 2 3 1 2 1 A A A A A A ∩ ∪ ∩ ∪ ∩ = 3. • Ni B A ⊆ , ni A B ⊆ . • Es más, B A ⊂ , luego A B A = ∩ • A C ⊆ , luego C C A = ∩ 4. 3 2 = p 5. • 5965 , 0 ) ( = Fumador P • 1754 , 0 ) ( = ∩ Fumador Mujer P • 5454 , 0 ) / ( = Mujer Fumador P 6. • 3 1 = a p • 5 1 5 4 = = P P p b • 12 1 5 3 5 = = P C p c 7. • 7 10 2 7 , 3 10 2 15 = = VR PR p a • 6 10 2 7 , 3 10 8 , 2 10 9 , 1 10 2 11 1 = + + + = VR PR PR PR p b 8. 29035 , 0 10 45 7 30 3 15 = ⋅ = C C C p
