examen de topo minera 2015.docx

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ANGULOANGULO

139 08' 2.5''537 13' 41''

255 30' 2.5''648 08' 49''

330 43' 15.5''745 37' 39''

457 44' 14.5''845 54' 36''

Coord. De A = (8421,100.24; 189,255.45) mts. Cota 3,0122 m.s.n.m A = AB = N 270 ELnea base AB = 520 mts.1= 24 32 62= 31 21 14 = 65 29 33=> 360 - 360 0 20= -204= 58 37 01Ca = = -2.5= 26 30 27 = 29 22 53 = 75 34 30 = 48 32 02SUMA DE ANGULOS: 360 0 20a) + = + = 37 13 41 = 45 37 39 = 39 08 2.5 = 30 43 15.5

(-) (+)

Ca = = - 12.25 = -12.25 = - 12.25 = + 12.25 = + 12.25b) + = + = 48 08 49 = 45 54 36 = 55 30 2.5 = 5744 14.5

(-) (+)

Ca = = - 0.25 = - 0.25 = - 0.25 = + 0.25 = + 0.25ANGULOC1C2C3dLog Sen par o imparC4ngulos Compensados

24 32 6- 2.5-12.252.7719.7817475-1737 1343

31 21 14 - 2.5-12.252.5889.8001234+1739 08 4.75

65 29 33- 2.5-0.251.8869.8720738-1748 08 29.25

58 37 01 - 2.5-0.251.4479.9159973+1755 30 16.75

26 30 27 - 2.5+ 12.252.0509.8541897-1745 37 31.75

29 22 53 - 2.5+ 12.253.5439.7082993+1730 43 42.25

75 34 30 - 2.5+ 0.252.0399.3562743-1745 54 16.75

48 32 02 - 2.5+ 0.251.3299.9271702+1757 49 29.25

17.663

log Sen par - log Sen impar = 039.3515908 - 39.3642853 = 0=> C4 = = 17.3 17Ley de Senos: = => AD = 456.98 m = => BC = 381.71 m = => DC = 556.385 m

X = LSEN(Z)Y= COS(Z)ex = -(Ex/P)Ley = -(Ey/P)L

LADOAZIMUTDISTANCIAXYexey

AB35520298.26425.959-0.2283.153

BC12743'26"381.71301.921-233.552-0.1682.315

CD26635'37.5"556.385-249.072-497.521-0.2443.374

AD30957'38.5"456.98-350.268293.501-0.2012.771

P = 1915.075x = 0.841y = -11.613