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Desarrolla: 1 -2 dx = -1 -1 = -1/2 1 _ 1 = -5 (x-1) 3 2(x-1) 2 -2 (-2) 2 (-3) 2 72 b) c) d) e) π 0 sen 3 x dx = π 0 (1-cos2x/2)dx = (x/2- 1/4sen2x) π 0 = π/2 b) c) d) e) INTEGRACIÓN DEFINIDA Actividades y Ejercicios

Integracion Definida

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INTEGRACIN DEFINIDA

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Actividades y Ejercicios

Desarrolla:

1-2 dx = -1 -1 = -1/2 1 _ 1 = -5

(x-1)3 2(x-1)2 -2 (-2)2 (-3)2 72

EMBED Equation.3 b) EMBED Equation.3 c) EMBED Equation.3 d) EMBED Equation.3 e) EMBED Equation.3

0 sen3x dx = 0 (1-cos2x/2)dx = (x/2-1/4sen2x)0 = /2

EMBED Equation.3 b) EMBED Equation.3 c) EMBED Equation.3 d) EMBED Equation.3 e) EMBED Equation.3

Calcular el rea del recinto limitado por la curva y = 4x x2y el eje OX.

En primer lugar se halla los puntos de corte con el eje OX para representar la curva y conocer los lmites de integracin.

0=4x-x2x=0x=4

En segundo lugar se calcula la integral:

A = 40 (4x-x2)dx = [2x2-x3/3]40 = 32/3u2

EMBED Equation.3 b) EMBED Equation.3 c) EMBED Equation.3 d) EMBED Equation.3 e) EMBED Equation.3

Hallar el volumen del tronco de cono engendrado por la rotacin alrededor OX del rea limitada por y = 6 x, y = 0, x = 0, x = 4.

EMBED Equation.3 b) EMBED Equation.3 c) EMBED Equation.3 d) EMBED Equation.3 e) EMBED Equation.3

Encuentre la longitud del arco de la curva EMBED Equation.3 del origen al punto EMBED Equation.3

L = 30 1+xdx = 21 t(2t)dt = 21 2t2dt = 2 21 t2dt

L = 2(t3/3)21

L = 2[(8/3)-(1/3)]

L = 2(7/3)

L = 14/3u

EMBED Equation.3 b) EMBED Equation.3 c) EMBED Equation.3 d) EMBED Equation.3 e) EMBED Equation.3

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