1.

xf(x)

-4-25.9816844

-3-16.9502129

-2-9.86466472

-1-4.63212056

0-1

11.71828183

25.3890561

315.0855369

444.59815

Del cambio de signos e toma a = 0 y b = 1

abxrf(xr)f(xa)f(xa)*f(xr)Error (%)

010.50.39872127-1-0.39872127

00.50.25-0.27847458-10.27847458100

0.250.50.3750.06436641-0.27847458-0.0179244133.3333333

0.250.3750.3125-0.10581831-0.278474580.0294677120

0.31250.3750.34375-0.02043803-0.105818310.002162729.09090909

0.343750.3750.3593750.02203347-0.02043803-0.000450324.34782609

0.343750.3593750.35156250.00081538-0.02043803-1.6665E-052.22222222

0.343750.35156250.34765625-0.00980686-0.020438030.000200431.12359551

0.347656250.35156250.34960938-0.00449463-0.009806864.4078E-050.55865922

Como el error es menor al 0.5% se toma como valor para la raz a xr = 0.34960938.

2.

De la grfica se tomara los puntos con un Para g1: x0 = g(x0)

x0g(x0)

g0-0.7-0.54663507

g1-0.54663507-0.63878371

g2-0.63878371-0.58554389

g3-0.58554389-0.61691811

g4-0.61691811-0.59866244

g5-0.59866244-0.6093599

g6-0.6093599-0.60311796

g7-0.60311796-0.606769

g8-0.606769-0.6046365

g9-0.6046365-0.60588309

g10-0.60588309-0.60515473

g11-0.60515473-0.60558042

g12-0.60558042-0.60533167

g13-0.60533167-0.60547704

g14-0.60547704-0.60539209

g15-0.60539209-0.60544173

Se toma la raz g15: x = -0.60544173