Upload
supershaman100
View
216
Download
0
Embed Size (px)
Citation preview
Proyecto de Aula # 1
f(x)=x2+3x-10
v ca 1b 3c -10
1mer paso
0=x2+3x-10
x1−2=−3±√32−4 (1)(−10)
2(1)
x1−2=−3±√9+40
2
x1−2=−3±√49
2
x1−2=−3±72
x1=−3+72
=42
= 2 A= (2,0)
x2=−3−72
=- 102
= -5 B= (-5,0)
2do paso
X= -b2a
= - 32
f(- 32)=(-
32 ¿2 +3(-
32 ) -10 =
94 -
92 -10 =
9−18−104 =
494
V= (- 32, 494
)
Grafique la Función Cuadrática f(x)=x2+3x-10
3er paso
F(0)=(0)2+3(0) -10 = -10 (0, -10)
Proyecto de Aula # 2
f(x)=x2+6x-16
v ca 1b 6c -16
1mer paso
0=x2+6x-16
x1−2=−6±√62−4 (1)(−16)
2(1)
x1−2=−6±√36+64
2
x1−2=−6±√100
2
x1−2=−6±102
x1=−6+102
=42
= 2 A= (2, 0)
x2=−6−102
=- 162
= -8 B= (-8, 0)
2do Paso
X= -b2a
= - 62
= -3
f(-3)=(-3 ¿2 +6(-3) -16 = 9 - 18 -16 = -25
Grafique la Función Cuadrática f(x)=x2+6x-16 si -2≤x<2
V= (- 3 ,-25)
3er paso
F(0)=(0)2+6(0) -16 = -16 = (0, -16)
Proyecto de Aula # 3
f(x)=x2
f(-3)= (-3¿2= 9 (-3,9)
f(-2)= (-2¿2= 4 (-2,4)
f(-1)= (-1¿2= 1 (-1,1)
f(0)= (0¿2= 0 (0,0)
f(1)= (1¿2= 1 (1,1)
f(2)= (2¿2= 4 (2,4)
f(3)= (3¿2= 9 (3,9)
f(x)=x2+4
f(-3)= (-3¿2+4= 9+4 (-3,13)
f(-2)= (-2¿2+4= 4+4 (-2,8)
f(-1)= (-1¿2+4= 1+4 (-1,5)
f(0)= (0¿2+4= 4 (0,4)
f(1)= (1¿2+4= 1 +4(1,5)
f(2)= (2¿2+4= 4+4(2,8)
Grafique la Función Cuadrática f(x)=x2; f(x)=x2+4; f(x)=x2-4 si X={-3,-2,-1,0,1,2,3}
f(3)= (3¿2+4= 9+4 (3,13)
f(x)=x2-4
f(-3)= (-3¿2-4= 9-4 (-3,5)
f(-2)= (-2¿2-4= 4-4 (-2,0)
f(-1)= (-1¿2-4= 1-4 (-1,-3)
f(0)= (0¿2-4= -4 (0,-4)
f(1)= (1¿2-4= 1 -4(1,-3)
f(2)= (2¿2-4= 4-4(2,0)
f(3)= (3¿2-4= 9-4 (3,-5)
Proyecto de Aula # 4
f(x)=(x−3)2
(x−3)2=0
√(x−3)2= √0
X-3=0
X=3 =(3,0)
F(0)=(0−3)2 =(−3)2 = 9 = (0,9)
Grafique la Función Cuadrática f(x)=(x-3¿2