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[ ˙ Q e m a h a,e m v h v,e m h h h,e ˙ Q perd −˙ m m ·h m ] ( t) ˙ m m (t) ( ( c p,a +ω f ( t) c p,v ) R m ( t) ) = d [ T s ( t) ] dt [ ˙ Q e 44.024838 ( T s T e )+1.005 ˙ m a T e +1.82 ˙ m v T e +72.8 ˙ m h −˙ m m T s ( 1.005+ 1.82 ω s )] ˙ m m ( ( 1.005 +1.82 ω s ) 0.287 ( 1 +0.6 ω s ) ) = d [ T s (t) ] dt ˙ Q e ( t )44.024838 T s +44.024838 T e + 1.005 ˙ m a T e + 1.82 ˙ m v T e +72.8 ˙ m h −˙ m m T s ( 1.005 +1.82 ω s ) ˙ m m ( ( 1.005+1.82 ω s ) 0.287 ( 1+0.6 ω s )) = d [ T s ( t ) ] dt Se definen constantes: Humedad relativa de entrada: ϕ e =0.5 Humedad relativa final: ϕ f =0.5 Caudal de aire: ˙ m a =20.028107 Caudal de vapor: ˙ m v =0.1453 Caudal de humidificador: ˙ m h =0.3622 Caudal de mezcla: ˙ m m =20.54 Humedad específica a la salida: ω s =0.02534

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[Qe+maha ,e+mvhv ,e+mhhh ,e−Q perd−mm · hm ](t)mm(t) ((cp , a+ωf (t )c p , v )−Rm(t))

=d [T s(t)]dt

[Qe−44.024838 (T s−T e)+1.005 maT e+1.82mv T e+72.8 mh−mmT s ( 1.005+1.82ωs ) ]mm ((1.005+1.82ωs )−0.287 (1+0.6ωs ))

=d [T s(t)]dt

Qe (t )−44.024838T s+44.024838T e+1.005 maT e+1.82mv T e+72.8 mh−mmT s (1.005+1.82ωs )mm ( (1.005+1.82ωs )−0.287 ( 1+0.6ωs ))

=d [T s(t)]dt

Se definen constantes:

Humedad relativa de entrada: ϕe=0.5

Humedad relativa final: ϕf=0.5

Caudal de aire: ma=20.028107

Caudal de vapor: mv=0.1453

Caudal de humidificador: mh=0.3622

Caudal de mezcla: mm=20.54

Humedad específica a la salida: ωs=0.02534

Qe ( t )−65.614822T s(t)+64.417531Te+26.3681615.605368

=d [T s(t)]dt

Qe ( t )15.605368

−65.614822T s (t )

15.605368+

64.417531T e15.605368

+ 26.3681615.605368

=d [T s(t) ]dt

En condiciones iniciales definidas:

Temperatura a la entrada: T e=20

Temperatura a la salida en el instante 0: T s (0 )=20

Qe ( t )15.605368

−65.614822T s ( t )

15.605368+1288.35062

15.605368+ 26.36816

15.605368=d [T s(t) ]dt

Qe ( t )15.605368

−65.614822T s ( t )

15.605368+8 4 .247855=

d [T s(t )]dt

d [T s( t)]dt

+65.614822T s (t )

15.605368−84.247855=

Qe ( t )15.605368

L[ d [T s(t )]dt

+65.614822T s (t )

15.605368−84.247855]=T (s )=4.204

s2 −83 .247855

s

L[ Q e (t )15.605368 ]=Q (s )=0.064081

s2

G (s )=T(s )

Q (s )=

4.204

s2−83.247855

s

0.064081s2

G (s )=T(s )

Q (s )=

4.204−83.247855 s

s2

0.064081s2

G (s )=T (s )Q (s )

=4.204−83.247855 s0.064081

Temperatura a la entrada: T e=25

Qe ( t )15.605368

−65.614822T s (t )

15.605368+1610.438275

15.605368+ 26.36816

15.605368=d [T s(t )]dt

Qe ( t )15.605368

−65.614822T s ( t )

15.605368+104.887398=

d [T s(t)]dt

d [T s( t)]dt

+65.614822T s (t )

15.605368−104.887398=

Qe ( t )15.605368

L[ d [T s(t )]dt

+65.614822T s (t )

15.605368−84.247855]=T (s )=4.204

s2 −83.247855

s

L[ Q e ( t )15.605368 ]=Q (s )=0.064081

s2

G (s )=T(s )

Q (s )=

4.204

s2−83.247855

s

0.064081s2

G (s )=T(s )

Q (s )=

4.204−83.247855 s

s2

0.064081s2

G (s )=T (s )Q (s )

=4.204−83.247855 s0.064081

Temperatura a la entrada: T e=30

Qe ( t )15.605368

−65.614822T s ( t )

15.605368+1932.52593

15.605368+ 26.36816

15.605368=d [T s(t )]dt

Qe ( t )15.605368

−65.614822T s ( t )

15.605368+125.526941=

d [T s( t)]dt

d [T s( t)]dt

+65.614822T s (t )

15.605368−125.526941=

Qe ( t )15.605368

L[ d [T s(t )]dt

+65.614822T s (t )

15.605368−84.247855]=T (s )=4.204

s2 −83.247855

s

L[ Q e (t )15.605368 ]=Q (s )=0.064081

s2

G (s )=T(s )

Q (s )=

4.204

s2−83.247855

s

0.064081s2

G (s )=T(s )

Q (s )=

4.204−83.247855 s

s2

0.064081s2

G (s )=T (s )Q (s )

=4.204−83.247855 s0.064081

Temperatura a la entrada: T e=35

Qe ( t )15.605368

−65.614822T s (t )

15.605368+2253.613585

15.605368+ 26.36816

15.605368=d [T s(t )]dt

Qe ( t )15.605368

−65.614822T s ( t )

15.605368+146.102403=

d [T s(t)]dt

d [T s( t)]dt

+65.614822T s (t )

15.605368−146.102403=

Qe ( t )15.605368

L[ d [T s(t )]dt

+65.614822T s (t )

15.605368−84.247855]=T (s )=4.204

s2 −83.247855

s

L[ Q e ( t )15.605368 ]=Q (s )=0.064081

s2

G (s )=T(s )

Q (s )=

4.204

s2−83.247855

s

0.064081s2

G (s )=T(s )

Q (s )=

4.204−83.247855 s

s2

0.064081s2

G (s )=T (s )Q (s )

=4.204−83.247855 s0.064081

Temperatura a la entrada: T e=40

Qe ( t )15.605368

−65.614822T s ( t )

15.605368+2576.70124

15.605368+ 26.36816

15.605368=d [T s(t)]dt

Qe ( t )15.605368

−65.614822T s ( t )

15.605368+166.806026=

d [T s(t)]dt

d [T s( t)]dt

+65.614822T s (t )

15.605368−166.806026=

Qe (t )15.605368

L[ d [T s(t )]dt

+65.614822T s (t )

15.605368−84.247855]=T (s )=4.204

s2 −83.247855

s

L[ Q e ( t )15.605368 ]=Q (s )=0.064081

s2

G (s )=T(s )

Q (s )=

4.204

s2−83.247855

s

0.064081s2

G (s )=T(s )

Q (s )=

4.204−83.247855 s

s2

0.064081s2

G (s )=T (s )Q (s )

=4.204−83.247855 s0.064081