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Page 1: EJERCICIO EXAMEN2

2.- HALLAR DFC

RELACIÓN ENTRE I/L

TRAMO AB=( 34 )( 13 )=0.25TRAMOBC=( 22 )=1TRAMOCD=( 23 )=0.67TRAMODE=( 22 )=1TRAMOEF=(11 )( 34 )=0.75

FACTOR DE DISTRIBUCIÓN

NUDO A

TRAMO AB→1

NUDO B

TRAMOBA= 0.250.25+1

=0.20

TRAMOBC= 10.25+1

=0.80

NUDO C

TRAMOCB= 11+0.67

=0.60

TRAMOCD= 0.671+0.67

=0.40

Page 2: EJERCICIO EXAMEN2

NUDO D

TRAMODC= 0.671+0.67

=0.40

TRAMODE= 11+0.67

=0.60

NUDOE

TRAMOEF= 0.751+0.75

=0.57

TRAMOED= 11+0.75

=0.43

NUDO F

TRAMOFE⇢1

DETERMINAR LOS MOMENTOS DE EMPOTRAMIENTO PERFECTO

TRAMO AB=3∗32

12=2.25

TRAMOBA=3∗32

12=−2.25

TRAMOBC=3∗22

12=1

TRAMOCB=3∗22

12=−1

TRAMOCD=3∗32

12=2.25

TRAMODC=3∗32

12=−2.25

TRAMODE=3∗22

12=1

TRAMOED=3∗22

12=−1

TRAMOEF=3∗12

12=0.25

TRAMOFE=3∗12

12=−0.25

Page 3: EJERCICIO EXAMEN2

A

REALIZAMOS EL PRIMER CROSS:

NUDO A FELEMENTO AB BA BC CB CD DC DE ED EF FE

F.D 1 0.2 0.8 0.6 0.4 0.4 0.6 0.57 0.43 1M.E.P 2.25 -2.25 1 -1 2.25 -2.25 1 -1 0.25 -0.25

SOLTAR -2.25 -1.125 0.125 0.25M.E.R 0 -3.375 1 -1 2.25 -2.25 1 -1 0.375 0

D 0 0.475 1.9 -0.75 -0.5 0.5 0.75 0.35625 0.26875 0T 0 0 -0.375 0.95 0.25 -0.25 0.178125 0.375 0 0D 0 0.075 0.3 -0.72 -0.48 0.02875 0.043125 -0.21375 -0.16125 0T 0 0 -0.36 0.15 0.014375 -0.24 -0.106875 0.0215625 0 0D 0 0.072 0.288 -0.098625 -0.06575 0.13875 0.208125 -0.01229063 -0.00927188 0T 0 0 -0.0493125 0.144 0.069375 -0.032875 -0.00614531 0.1040625 0 0D 0 0.0098625 0.03945 -0.128025 -0.08535 0.01560813 0.02341219 -0.05931563 -0.04474688 0T 0 0 -0.0640125 0.019725 0.00780406 -0.042675 -0.02965781 0.01170609 0 0D 0 0.0128025 0.05121 -0.01651744 -0.01101163 0.02893313 0.04339969 -0.00667247 -0.00503362 0T 0 0 -0.00825872 0.025605 0.01446656 -0.00550581 -0.00333624 0.02169984 0 0D 0 0.00165174 0.00660698 -0.02404294 -0.01602863 0.00353682 0.00530523 -0.01236891 -0.00933093 0T 0 0 -0.01202147 0.00330349 0.00176841 -0.00801431 -0.00618446 0.00265261 0 0D 0 0.00240429 0.00961718 -0.00304314 -0.00202876 0.00567951 0.00851926 -0.00151199 -0.00114062 0T 0 0 -0.00152157 0.00480859 0.00283975 -0.00101438 -0.000756 0.00425963 0 0D 0 0.00030431 0.00121726 -0.004589 -0.00305934 0.00070815 0.00106222 -0.00242799 -0.00183164 0T 0 0 -0.0022945 0.00060863 0.00035407 -0.00152967 -0.00121399 0.00053111 0 0D 0 0.0004589 0.0018356 -0.00057762 -0.00038508 0.00109747 0.0016462 -0.00030273 -0.00022838 0

SUMATORIA 0 -2.72551575 2.72551575 -1.44736944 1.44736944 -2.10855098 2.10855098 -0.41091605 0.41091605 0

B C D E

HALLAMO S LAS REACCIONES

RC=4.28

RD=4.72

RA=3.51

RB=5.41

RB=7.64

RC=2.36

RD=3.85

ℜ=2.15

A

Page 4: EJERCICIO EXAMEN2

HALLANDO EL DIAGRAMA DE MOMENTOS FLECTORES

HALLANDO EL DIAGRAMA DE FUERZA CORTANTE

ℜ=¿6.91

RF=1.09


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