Presentation finale

Thesis Defense

CHEMALY Chantal

UNIVERSITE LIBANAISE - FACULTE DE GENIE&

UNIVERSITE SAINT-JOSEPHFACULTE D’INGENIERIE– DEPARTEMENT DES

ETUDES DOCTORALES

STUDY OF THE POSSIBILITIES OF A TRI-GENERATION PRODUCTION: HEAT, COLD AND

ELECTRICITY, FROM BIOMASS

Committee Members:Dr. BECHRA Rami (Advisor)Dr. MOURTADA AdelDr. YOUNES Rafic October 18, 2016

1

Outline

Introduction - Scope of thesis

Methodology

Results Sensibility Study Application

Conclusion & Future Work

2

Outline


Methodology



3

Introduction 4

A Solution Tri-generation

High efficiencyEnvironmental protectionEconomic benefits

F= Biomass

Outline


Methodology



5

Methodology 6

Biomass flow rate = 57 t/hBiomass moisture content = 0.49%

Methodology 7

HHV=17.919MJ/KgEfficiency = 70%

Energy produced = (biomass flow x HHV) x burner efficiency

Methodology 8

Operating Pressure = 90 bar*Superheating Temperature = 553.31°C*

Total steam produced = 149 t/h

* Bechara, R. (2015). Methodology for the designof optimal processes: application to sugarcane conversion processes (Doctoral dissertation, Université Claude Bernard-Lyon I).

Methodology 9

Input Steam Pressure = 90 barOutput Steam Pressure = 3 bar*

Output Steam temperature = 150 °C*Total Power produced = 25 MW (Steam turbine calculator)


Methodology 10

Output Pressure = 0.7 bar Output Temperature = 150°C Reheat = 220°COutput water temperature = 50°C Efficiency of exchange = 0.8

Power produced = 8MW (for VHvsLP=1)Hot water Produced = 2517.5 t/h (for VHvsLP=0)

VHvsLP between 0 & 1

BECHARA Rami

Here you can introduce the first choice variableIndicate that there is a conflict hence the need for this variable. Indicate its rangeHighlight the default value given for this variable which lead to the obtained valuesMention some characteristics of the two systems

Methodology 11

Input Temperature= 90°C*COP=1.4*

Cold produced=Heat at the input of the chiller x Cooling Efficiency

VCool between 0 & 1

* Maraver, D., Sin, A., Royo, J., & Sebastián, F. (2013). Assessment of CCHP systems based on biomass combustion for small-scale applications through a review of the technology and analysis of energy efficiency parameters. Applied energy, 102, 1303-1313.

BECHARA Rami

Literal expression better than numbers. Question that will be asked: what do the numbers represent?Introduce the second variableIndicate its range

Methodology 12

Heat transfer efficiency = 0.8*Cold produced with flue gas recovery = 54.966 MW

VFGR between 0 & 1


BECHARA Rami

Interesting to include only amount of cold produced through flue gas recovery. Indicate assumptions since they give the valuesIntroduce the third variable

Outline


Methodology



13

Results 14

0 0.2 0.4 0.6 0.8 1 1.20

10

20

30

40

50

60

Total Energy Produced for Diferent Values of VHvsLP

Vcool=1 Vrecovery=1 Vcool=0 Vrecovery=1

Vcool=1 VRecovery=0 Vcool=0 Vrecovery=0

VH vs LP

Ener

gy P

rodu

ced

(MW

)

BECHARA Rami

Good Figure. Increase Size. Change Range. Relocate Legend. Should be more visibleInclude variable names in axis along with dimensionsThis Figure should have a title. see sensitivity analysisBelow figures are but an example of this Figure

Outline


Methodology



15

Results 16

MP Turbine Power LP Turbine Power Hot Water Cold Total Energy Produced

0

20

40

60

80

100

120

Ener

gy P

rodu

ced

(MW

)

MP Turbine Power LP Turbine Power Hot Water Cold Total Energy Produced0

20

40

60

80

100

120

Case1: without cold production and without flue gas recovery (VCool=0 & VFGR=0)Case2: with cold production and without flue gas recovery (VCool=1 & VFGR=0)Case3: with cold production and with flue gas recovery (VCool=1 & VFGR=1)

Ener

gy P

rodu

ced

(MW

)

VHvsLP=0

VHvsLP=1

BECHARA Rami

Find a way to merge slides 21 and 22case1 , 2 and 3 legends could be merged into one legend below the figures with explanations given

Outline


Methodology



17

Results 18

Energy type Energy sales

Electric power 87 $/MW

Heating 8.4 $/MW

Cold 24.9 $/MW

Results 18

VHvsLP=0

VHvsLP=1


0

1000

2000

3000

4000

5000

Ener

gy S

ales

($)


0

1000

2000

3000

4000

5000

Case1: without cold production and without flue gas recovery (VCool=0 & VFGR=0)Case2: with cold production and without flue gas recovery (VCool=1 & VFGR=0)Case3: with cold production and with flue gas recovery (VCool=1 & VFGR=1)

Ener

gy S

ales

($)

Outline


Methodology



19

Results 20

Application : Case 1

Biomass flow rate is an additional variable

Energy type Requirements Energy sales

Electric power 13.5 MW 87 $/MW

Heating 13 MW 8.4 $/MW

Cold 18 MW 24.9 $/MW

BECHARA Rami

Here put colors to tables since it is a presentation and should look artful.Make sure you explain well the principleSay that biomass flow rate is includedAn introductory slide is important herePut first table in a separate slide with explanations

Results 21

Type of

energy

Energy

required

Energy

produced

Delta

E

Price of energy

supplemented

from market*

Total

electric

power

13.5 MW 13.5 MW 0 $0

Heating 13 MW 12.7 MW 0.308 $2.6

Cold 18 MW 18. MW 0 $0

Total

energy58 MW 44.2 MW

Variables Values taken

VHvsLP 0.554

VCool 1

VFGR 1

Biomass flow 26.576 t/h


BECHARA Rami

Here put colors to tables since it is a presentation and should look artful.Make sure you explain well the principleSay that biomass flow rate is includedAn introductory slide is important herePut first table in a separate slide with explanations

Results 22

Energy type Requirements Energy sales

Electricity 13.5 MW 87 $/MW

Heating 13 MW 30 $/MW

Cold 18 MW 23 $/MW


Results 23


Energy type

Energy required

Energy produced

Delta E

Price of energy

supplemented from market*

Total electric power

13.5 MW13.500

MW0 $0

Heating 13 MW13.000

MW0 $0

Cold 18 MW17.786

MW0.214 $4.912

Total energy

58 MW44.286

MW

Variables Values taken

VHvsLP 0.5442

VCool 1

VFGR 1

Biomass flow 26.647 t/h

Outline


Methodology



24

Conclusion & Future Work 25

Further Studies

Greenhouse gas

emissions

Running Cost

Installation cost

CCHP system with large potential of economical efficiency and energy savings

Questions 26

Engineering

Presentation finale