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INSTITUTO TECNOLOGICO DE DURANGO Departamento de Ingeniería Bioquímica Fórmulas mínimas en base C-mol Materia: INGENIERÍA DE BIORREACTORES Docente: Dr. NICOLÁS ÓSCAR SOTO CRUZ Alumno: JOSÉ NABOR HARO GONZÁLEZ

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Page 1: C-mol

INSTITUTO TECNOLOGICO DE DURANGO

Departamento de Ingeniería Bioquímica

Fórmulas mínimas en base C-molMateria: INGENIERÍA DE BIORREACTORES

Docente: Dr. NICOLÁS ÓSCAR SOTO CRUZ

Alumno: JOSÉ NABOR HARO GONZÁLEZ

Septiembre de 2015 Durango

Page 2: C-mol

1. Acetaldehído

FormulaGeneral :C2H 4O

Pesomolecular :12 (2 )+1 (4 )+16 (1 )=44 gmol

NumerodeC=2

NumerodeC baseC−mol=22=1

Numerode H baseC−mol= 42=2

NumerodeObaseC−mol=12=0.5

FormulabaseC−mol :CH2O0.5

Pesomolecular baseC−mol :12 (1 )+1 (2 )+16 ( .5 )=22 gC−mol

2. Ácido acético

FormulaGeneral :C2H 4O2

Pesomolecular :12 (2 )+1 (4 )+16 (2 )=60 gmol

NumerodeC=2

NumerodeC baseC−mol=22=1

Numerode H baseC−mol= 42=2

NumerodeObaseC−mol=22=1

FormulabaseC−mol :CH2O

Pesomolecul ar baseC−mol :12 (1 )+1 (2 )+16 (1 )=30 gC−mol

3. Acetona

FormulaGeneral :C3H 6O

Pesomolecular :12 (3 )+1 (6 )+16 (1 )=58 gmol

Page 3: C-mol

NumerodeC=3

NumerodeC baseC−mol=33=1

Numerode H baseC−mol=63=2

NumerodeObaseC−mol=13=0.33

FormulabaseC−mol :CH2O0.33

Pesomolecular baseC−mol :12 (1 )+1 (2 )+16 (0.33 )=19.28 gC−mol

4. N-butanol

FormulaGeneral :C4H 10O

Pesomolecular :12 (4 )+1 (10 )+16 (1 )=64 gmol

NumerodeC=4

NumerodeC baseC−mol=44=1

Numerode H baseC−mol=104

=2 .5

NumerodeObaseC−mol= 14=0.25

FormulabaseC−mol :CH2 .5O0.25

Pesomolecular baseC−mol :12 (1 )+1 (2.5 )+16 (0.25 )=18.5 gC−mol

5. Butírico

F ormulaGeneral :C4H 8O 2

Pesomolecular :12 (4 )+1 (8 )+16 (2 )=88 gmol

NumerodeC=4

NumerodeC baseC−mol=44=1

Page 4: C-mol

Numerode H baseC−mol= 84=2

NumerodeObaseC−mol= 24=0.5

FormulabaseC−mol :CH2O0.5

Pesomolecular baseC−mol :12 (1 )+1 (2 )+16 (0.5 )=22 gC−mol

6. Cítrico

F ormulaGeneral :C6H 8O7

Pesomolecular :12 (6 )+1 (8 )+16 (7 )=192 gmol

NumerodeC=6

NumerodeC baseC−mol=66=1

Numer ode H baseC−mol=86=1.33

NumerodeObaseC−mol=76=1.16

FormulabaseC−mol :CH1.33O1.16

Pesomolecular baseC−mol :12 (1 )+1 (1.33 )+16 (1.16 )=31.89 gC−mol

7. Etano

F∨mulaGeneral :C2H 6

Pesomolecular :12 (2 )+1(6)=30 gmol

NumerodeC=2

NumerodeC baseC−mol=22=1

Numerode H baseC−mol=62=3

FormulabaseC−mol :CH3

Page 5: C-mol

Pesomolecular baseC−mol :12 (1 )+1 (3 )=15 gC−mol

8. Etanol

F ormulaGeneral :C2H 6O

Pesomolecular :12 (2 )+1(6)+16 (1 )=46 gmol

NumerodeC=2

NumerodeC baseC−mol=22=1

Numerode H baseC−mol=62=3

NumerodeObaseC−mol=12=0.5

FormulabaseC−mol :CH3O0.5

Pesomolecular baseC−mol :12 (1 )+1 (3 )+16 (0.5 )=23 gC−mol

9. Formaldehido

F ormulaGeneral :C H 2O

Pesomolecular :12 (1 )+1(2)+16 (1 )=30 gmol

NumerodeC=1

NumerodeC baseC−mol=11=1

Numerode H baseC−mol=21=2

NumerodeObaseC−mol=11=1

FormulabaseC−mol :C H 2O

Pesomolecular baseC−mol :12 (1 )+1(2)+16 (1 )=30 gC−mol

10.Fórmico

Page 6: C-mol

F ormulaGeneral :C H 2O2

Pesomolecular :12 (1 )+1(2)+16 (2 )=46 gmol

NumerodeC=1

NumerodeC baseC−mol=11=1

Numerode H baseC−mol=21=2

NumerodeObaseC−mol=21=2

FormulabaseC−mol :C H 2O2

Pesomolecular baseC−mol :12 (1 )+1(2)+16 (2 )=46 gC−mol

11.Fructosa

F ormulaGeneral :C6H 12O6

Pesomolecular :12 (6 )+1(12)+16 (6 )=180 gmol

NumerodeC=6

NumerodeC baseC−mol=66=1

Numerode H baseC−mol=126

=2

NumerodeObaseC−mol=66=1

FormulabaseC−mol :C H 2O

Pesomolecular baseC−mol :12 (1 )+1(2)+16 (1 )=30 gC−mol

12.Fumárico

F ormulaGeneral :C4H 4O4

Page 7: C-mol

Pe somolecular :12 (4 )+1(4 )+16 (4 )=116 gmol

NumerodeC=4

NumerodeC baseC−mol=44=1

Numerode H baseC−mol= 44=1

NumerodeObaseC−mol= 44=1

FormulabaseC−mol :CHO

Pesomolecular baseC−mol :12 (1 )+1(1)+16 (1 )=29 gC−mol

13.Galactosa

F ormulaGeneral :C6H 12O6

Pesomolecular :12 (6 )+1(12)+16 (6 )=180 gmol

NumerodeC=6

NumerodeC baseC−mol=66=1

Numerode H baseC−mol=126

=2

NumerodeObaseC−mol=66=1

FormulabaseC−mol :C H 2O

Pesomolecular baseC−mol :12 (1 )+1(2)+16 (1 )=30 gC−mol

14.Glucosa

F ormulaGeneral :C6H 12O6

Pesomolecular :12 (6 )+1(12)+16 (6 )=180 gmol

NumerodeC=6

Page 8: C-mol

NumerodeC baseC−mol=66=1

Numerode H baseC−mol=126

=2

NumerodeObaseC−mol=66=1

FormulabaseC−mol :C H 2O

Pesomolecular baseC−mol :12 (1 )+1(2)+16 (1 )=30 gC−mol

Page 9: C-mol

15.Glicerol

F ormulaGeneral :C3H 8O3

Pesomolecular :12 (3 )+1(8)+16 (3 )=92 gmol

NumerodeC=3

NumerodeC baseC−mol=33=1

Numerode H baseC−mol=83=2.66

NumerodeObaseC−mol=33=1

FormulabaseC−mol :C H 2.66O

Pesomolec ular baseC−mol :12 (1 )+1(2.66)+16 (1 )=30.66 gC−mol

16. Isopropanol

F ormulaGeneral :C3H 8O

Pesomolecular :12 (3 )+1(8)+16 (1 )=60 gmol

NumerodeC=3

NumerodeC baseC−mol=33=1

Numerode H baseC−mol=83=2.66

NumerodeObaseC−mol=13=.33

FormulabaseC−mol :C H 2.66O.33

Pesomolecular baseC−mol :12 (1 )+1(2.66)+16 ( .33 )=20 gC−mol

17.Láctico

F∨mulaGeneral :C3H 6O3

Pesomolecular :12 (3 )+1(6)+16 (3 )=90 gmol

Page 10: C-mol

NumerodeC=3

NumerodeC baseC−mol=33=1

Numerode H baseC−mol=63=2

NumerodeObaseC−mol=33=1

FormulabaseC−mol :C H 2O

Pesomolecular baseC−mol :12 (1 )+1(2)+16 (1 )=30 gC−mol

18.Lactosa

F ormulaGeneral :C12H 22O11

Pesomolecular :12 (12 )+1(22)+16 (11)=342 gmol

NumerodeC=12

NumerodeC baseC−mol=1212

=1

Numerode H baseC−mol=2212

=1.83

NumerodeObaseC−mol=1112

=0.91

FormulabaseC−mol :C H 1.83O0.91

Pesomolecular baseC−mol :12 (1 )+1(1.83)+16 (0.91 )=28.39 gC−mol

19.Málico

F ormulaGeneral :C4H 6O5

Pesomolecular :12 (4 )+1(6)+16 (5 )=134 gmol

NumerodeC=4

NumerodeC baseC−mol=44=1

Page 11: C-mol

Numerode H baseC−mol= 64=1.5

NumerodeObaseC−mol=54=1.25

FormulabaseC−mol :C H 1.5O1.25

Pesomolecular baseC−mol :12 (1 )+1(1.5)+16 (0.91 )=33.5 gC−mol

20.Metano

F ormulaGeneral :C H 4

Pesomolecular :12 (1 )+1(4)=16 gmol

NumerodeC=1

NumerodeC baseC−mol=11=1

Numerode H baseC−mol= 41=4

FormulabaseC−mol :C H 4

Pesomolecular baseC−mol :12 (1 )+1(4)=16 gC−mol

21.Metanol

F ormulaGeneral :C H 4O

Pesomolecular :12 (1 )+1(4)+16 (1 )=32 gmol

NumerodeC=1

NumerodeC baseC−mol=11=1

Numerode H baseC−mol= 41=4

NumerodeObaseC−mol=11=1

FormulabaseC−mol :C H 4O

Page 12: C-mol

Pesomolecular baseC−mol :12 (1 )+1(4)+16 (1 )=32 gC−mol

22.Oxálico

F ormula≥neral:C2H 2O4

Pesomolecular :12 (2 )+1(2)+16 (4 )=90 gmol

NumerodeC=2

NumerodeC baseC−mol=22=1

Numerode H baseC−mol=22=1

NumerodeObaseC−mol= 42=2

FormulabaseC−mol :CHO2

Pesomolecular baseC−mol :12 (1 )+1(1)+16 (2 )=45 gC−mol

23.Palmítico

F ormulaGeneral :C16H 32O2

Pesomolecular :12 (16 )+1 (32 )+16 (2 )=256 gmol

NumerodeC=16

NumerodeC baseC−mol=1616

=1

Numerode H baseC−mol=3216

=2

NumerodeObaseC−mol= 216

=0.125

FormulabaseC−mol :C H 2O0.125

Pesomolecular baseC−mol :12 (1 )+1(2)+16 (0.125 )=16 gC−mol

24.Propano

F ormulaGeneral :C3H 8

Page 13: C-mol

Pesomolecular :12 (3 )+1 (8 )=4 4 gmol

NumerodeC=3

NumerodeC baseC−mol=33=1

Numerode H baseC−mol=83=2.66

FormulabaseC−mol :C H 2 .66

Pesomolecular baseC−mol :12 (1 )+1(2 .66)=14.66 gC−mol

25.Propiónico

F ormulaGeneral :C3H 6O2

Pesomolecular :12 (3 )+1 (6 )+16 (2 )=74 gmol

NumerodeC=3

NumerodeC baseC−mol=33=1

Numerode H baseC−mol=63=2

NumerodeObaseC−mol=23=0.66

FormulabaseC−mol :C H 2O0.66

Pesomolecular baseC−mol :12 (1 )+1(2)+16 (0.66 )=24.56 gC−mol

26.Succinico

F ormulaGeneral :C4H 6O 4

Pesomolecular :12 (4 )+1 (6 )+16 (4 )=118 gmol

NumerodeC=4

NumerodeC baseC−mol=44=1

Page 14: C-mol

Numerode H baseC−mol= 64=1.5

NumerodeObaseC−mol=44=1

FormulabaseC−mol :C H 1.5O

Pesomolecular baseC−mol :12 (1 )+1(1.5)+16 (1 )=29.5 gC−mol

27.Sacarosa

F ormulaGeneral :C12H 22O11

Pesomolecular :12 (12 )+1 (22 )+16 (11)=342 gmol

NumerodeC=12

NumerodeC baseC−mol=1212

=1

Numerode H baseC−mol=2212

=1.83

NumerodeObaseC−mol=1112

=0.91

FormulabaseC−mol :C H 1.83O0.91

Pesomolecular baseC−mol :12 (1 )+1(1.83)+16 (0.91 )=28.39 gC−mol