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8/18/2019 Jarraitasuna4Gaia
1/2
f a limx→a
f (x) =
f (a)
∀ > 0 ∃δ > 0 /
|x − a| < δ
x ∈ D⇒ |f (x) − f (a)| < .
f (x) = k
f (x) = x
R
f
g
a
f + g
f g f /g g (a) = 0 a
f
a
g
f (a)
g ◦ f a
f
a
{xn} → a =⇒ {f (xn)} → f (a)
f a
limx→a
+f (x) = f (a)
limx→a
−
f (x) = f (a)
• limx→a
f (x) = l ∈ R limx→a
f (x) = f (a)
f (a)
• limx→a
+f (x) = lim
x→a−
f (x)
limx→a+f (x) − limx→a−f (x)
a
• limx→a
f (x) = ∞
8/18/2019 Jarraitasuna4Gaia
2/2
f
[a, b]
(a, b)
a
b
f [a, b] f (a) f (b) < 0
c ∈ (a, b) / f (c) = 0
f
[a, b]
C
f (a)
f (b)
µ ∈ (a, b) / f (µ) = C
f [a, b]
∃ x1, x2 ∈ [a, b] / f (x1) ≤ f (x) ≤ f (x2) ∀x ∈ [a, b] .
f
[a, b]