7/25/2019 RelacionY

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"Calcular la relacion y/D de un colector de 300 mm, que conduce 5o lt/seg a unapendiente de 3.5 o/00

SolucionDatosD = 300 mm = 0.3 mQ = 50 lt/ segS = 3.5 = 0.0035

Q0 = 0.3115 (1/n) (D)^8/3 (S)^1/2Q0 = 0.3115 (1/0.013) (0.3)^8/3 (0.0035)^1/2Q0 = 0.05717 m3/segQ0 = 57.17 lt / seg

Con la relacion

q/Q0 =q/Q0 = 50 / 57.17q/Q0 = 0.87

Hallamos con la tabla

v/v0 = 1,125y/D = 0.72

V0 = (0.397 (D)^2/3 (S)^1/2) / nV0 = (0.397 (0.3)^2/3 (0.0035)^1/2) / 0.013V0 = 0.72 m/s

Hallamos la Velocidad real

V = v/v0 * v0V = 1.125 * 0.72V = 0.82 m/s

Hallamos Rh

Rh = ((V * n) / (S^1/2))^3/2Rh = (0.82 * 0.013 / 0.0035 ^1/2) ^3/2Rh = 0.076"